Difference between revisions of "Edge template VI1a"
(moved the part, and rewritten a few of things) |
(→The remaining intrusion on the fourth row: -- starting the solution) |
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Bi4 | Bi4 | ||
</hex> | </hex> | ||
+ | |||
+ | Red should move here: | ||
+ | |||
+ | <hex> | ||
+ | R7 C14 Q0 | ||
+ | 1:BBBBBBBBBRBBBBB | ||
+ | Sa2 Sb2 Sc2 Sd2 Se2 Sf2 Sg2 Sh2 Rj2 Sl2 Sm2 Sn2 | ||
+ | Sa3 Sb3 Sc3 Sd3 Se3 Sf3 Sm3 Sn3 | ||
+ | Sa4 Sb4 Sc4 Sd4 Sn4 | ||
+ | Sa5 Sb5 | ||
+ | Sa6 | ||
+ | |||
+ | Bi4 Rh3 | ||
+ | </hex> | ||
+ | |||
+ | This gives Red several immediate threats: | ||
+ | From III1a: | ||
+ | <hex> | ||
+ | R7 C14 Q0 | ||
+ | 1:BBBBBBBBBRBBBBB | ||
+ | Sa2 Sb2 Sc2 Sd2 Se2 Sf2 Sg2 Sh2 Rj2 Sl2 Sm2 Sn2 | ||
+ | Sa3 Sb3 Sc3 Sd3 Se3 Sf3 Sm3 Sn3 | ||
+ | Sa4 Sb4 Sc4 Sd4 Sn4 | ||
+ | Sa5 Sb5 | ||
+ | Sa6 | ||
+ | |||
+ | Bi4 Rh3 | ||
+ | Rg5 | ||
+ | Pg4 Ph4 | ||
+ | Ph5 | ||
+ | Pf6 Pg6 Ph6 | ||
+ | Pe7 Pf7 Pg7 Ph7 | ||
+ | </hex> | ||
+ | |||
+ | From III1a again: | ||
+ | <hex> | ||
+ | R7 C14 Q0 | ||
+ | 1:BBBBBBBBBRBBBBB | ||
+ | Sa2 Sb2 Sc2 Sd2 Se2 Sf2 Sg2 Sh2 Rj2 Sl2 Sm2 Sn2 | ||
+ | Sa3 Sb3 Sc3 Sd3 Se3 Sf3 Sm3 Sn3 | ||
+ | Sa4 Sb4 Sc4 Sd4 Sn4 | ||
+ | Sa5 Sb5 | ||
+ | Sa6 | ||
+ | |||
+ | Bi4 Rh3 | ||
+ | Rg5 | ||
+ | Pg4 Ph4 | ||
+ | Pf5 | ||
+ | Pe6 Pf6 Pg6 | ||
+ | Pd7 Pe7 Pf7 Pg7 | ||
+ | </hex> | ||
+ | |||
+ | From IV1a: | ||
+ | <hex> | ||
+ | R7 C14 Q0 | ||
+ | 1:BBBBBBBBBRBBBBB | ||
+ | Sa2 Sb2 Sc2 Sd2 Se2 Sf2 Sg2 Sh2 Rj2 Sl2 Sm2 Sn2 | ||
+ | Sa3 Sb3 Sc3 Sd3 Se3 Sf3 Sm3 Sn3 | ||
+ | Sa4 Sb4 Sc4 Sd4 Sn4 | ||
+ | Sa5 Sb5 | ||
+ | Sa6 | ||
+ | |||
+ | Bi4 Rh3 | ||
+ | Rg4 | ||
+ | Pf4 | ||
+ | Pd5 Pe5 Pf5 Pg5 Ph5 | ||
+ | Pc6 Pd6 Pe6 Pf6 Pg6 Ph6 | ||
+ | Pb7 Pc7 Pd7 Pe7 Pf7 Pg7 Ph7 | ||
+ | </hex> | ||
+ | |||
+ | From IV1b: | ||
+ | <hex> | ||
+ | R7 C14 Q0 | ||
+ | 1:BBBBBBBBBRBBBBB | ||
+ | Sa2 Sb2 Sc2 Sd2 Se2 Sf2 Sg2 Sh2 Rj2 Sl2 Sm2 Sn2 | ||
+ | Sa3 Sb3 Sc3 Sd3 Se3 Sf3 Sm3 Sn3 | ||
+ | Sa4 Sb4 Sc4 Sd4 Sn4 | ||
+ | Sa5 Sb5 | ||
+ | Sa6 | ||
+ | |||
+ | Bi4 Rh3 | ||
+ | Rg4 | ||
+ | Pf4 Ph4 | ||
+ | Pd5 Pe5 Pf5 Pg5 Ph5 Pi5 | ||
+ | Pc6 Pd6 Pe6 Pg6 Ph6 Pi6 | ||
+ | Pb7 Pc7 Pd7 Pe7 Pf7 Pg7 Ph7 Pi7 | ||
+ | </hex> | ||
+ | |||
+ | The intersection of all of these leaves: | ||
+ | <hex> | ||
+ | R7 C14 Q0 | ||
+ | 1:BBBBBBBBBRBBBBB | ||
+ | Sa2 Sb2 Sc2 Sd2 Se2 Sf2 Sg2 Sh2 Rj2 Sl2 Sm2 Sn2 | ||
+ | Sa3 Sb3 Sc3 Sd3 Se3 Sf3 Sm3 Sn3 | ||
+ | Sa4 Sb4 Sc4 Sd4 Sn4 | ||
+ | Sa5 Sb5 | ||
+ | Sa6 | ||
+ | |||
+ | Bi4 Rh3 | ||
+ | Pg4 | ||
+ | Pg5 | ||
+ | Pg6 | ||
+ | Pe7 Pf7 Pg7 | ||
+ | </hex> | ||
+ | |||
+ | So we must deal with each of these responses. (Which will not be too hard!) | ||
+ | |||
+ | To be continued.... | ||
===The remaining intrusion on the fifth row=== | ===The remaining intrusion on the fifth row=== |
Revision as of 05:02, 14 January 2009
This template is the first one stone 6th row template for which a proof has been handwritten.
Elimination of irrelevant Blue moves
Red has a couple of direct threats to connect, using smaller templates. Blue must play in the carrier of these threats in order to counter them. To prevent Red from connecting Blue must play in the intersection of Red's threats carriers.
edge template IV1a
edge template IV1b
Using the parallel ladder trick
6 moves can furthermore be discared thanks to the Parallel ladder trick. Of course, symmetry will cut our work in half!
We can dispose of 3 moves on the left (and, using mirror symmetry, the corresponding 3 moves on the right), as follows:
At this point, we can use the Parallel ladder trick as follows:
Remaining possibilities for Blue
Blue's first move must be one of the following:
Specific defence
For the moves that intersect all the carriers, Red has to find specific answers. Let's deal with the remaining intrusions!
One remaining intrusion on the first row
The other remaining intrusion on the first row
The remaining intrusion on the second row
The remaining intrusion on the third row
The remaining intrusion on the fourth row
Red should move here:
This gives Red several immediate threats: From III1a:
From III1a again:
From IV1a:
From IV1b:
The intersection of all of these leaves:
So we must deal with each of these responses. (Which will not be too hard!)
To be continued....