Difference between revisions of "Hex theory"
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Roland Illig (Talk | contribs) (restored) |
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* The game can not end in a [[draw]]. ([http://javhar1.googlepages.com/hexcannotendinadraw Proofs] on Javhar's page) | * The game can not end in a [[draw]]. ([http://javhar1.googlepages.com/hexcannotendinadraw Proofs] on Javhar's page) | ||
− | * The [[first player]] has a [[winning strategy]]. | + | * The [[Red (player)|first player]] has a [[winning strategy]]. |
− | * When playing with the swap option, the second player has a winning strategy. | + | * When playing with the [[swap]] option, the second player has a winning strategy. |
== See also == | == See also == | ||
[[Open problems]] | [[Open problems]] |
Revision as of 19:46, 27 November 2007
Unlike many other games, it is possible to say certain things about Hex, with absolute certainty. While, for example, nobody seriously believes that black has a winning strategy in chess, nobody has been able to prove that such a strategy doesn't exist. In Hex, on the other hand, a simple argument can show that the second player certainly does not have a winning strategy from the starting position (when the swap option is not used). Whether this makes Hex a better game is of course debatable, but many find this attribute charming.
The most important properties of Hex are the following:
- The game can not end in a draw. (Proofs on Javhar's page)
- The first player has a winning strategy.
- When playing with the swap option, the second player has a winning strategy.