Difference between revisions of "Edge template VI1a"

From HexWiki
Jump to: navigation, search
(The remaining intrusion on the third row (stub): moved contents)
(Remaining possibilities for Blue: cell links (new feature !))
Line 116: Line 116:
 
Sa6
 
Sa6
  
Pi3 Pj3
+
[[#The_remaining_intrusion_on_the_fifth_row|Pi3]] [[#The_remaining_intrusion_on_the_fifth_row|Pj3]]
Pi4
+
[[Template_VI1/Intrusion_on_the_4th_row|Pi4]]
Ph5 Pi5
+
[[Template_VI1/Intrusion_on_the_3rd_row|Ph5]]
Pg6 Pi6
+
[[Template_VI1/Intrusion_on_the_3rd_row|Pi5]]
Pf7 Pg7 Ph7 Pi7
+
[[#The_remaining_intrusion_on_the_second_row_.28stub.29|Pg6]] [[#The_remaining_intrusion_on_the_second_row_.28stub.29|Pi6]]
 +
[[#One_remaining_intrusion_on_the_first_row_.28stub.29|Pf7]]
 +
[[#The_other_remaining_intrusion_on_the_first_row_.28stub.29|Pg7]]
 +
[[#The_other_remaining_intrusion_on_the_first_row_.28stub.29|Ph7]] [[#One_remaining_intrusion_on_the_first_row_.28stub.29|Pi7]]
 
</hex>
 
</hex>
  

Revision as of 23:35, 10 March 2009

This template is the first one stone 6th row template for which a proof has been handwritten.

Elimination of irrelevant Blue moves

Red has a couple of direct threats to connect, using smaller templates. Blue must play in the carrier of these threats in order to counter them. To prevent Red from connecting Blue must play in the intersection of Red's threats carriers.

edge template IV1a

edge template IV1b

Using the parallel ladder trick

6 moves can furthermore be discarded thanks to the Parallel ladder trick. Of course, symmetry will cut our work in half!

We can dispose of 3 moves on the left (and, using mirror symmetry, the corresponding 3 moves on the right), as follows:

132546

At this point, we can use the Parallel ladder trick as follows:

7561324

Remaining possibilities for Blue

Blue's first move must be one of the following:

WARNING: Unrecognized token: [[#The_remaining_intrusion_on_the_fifth_row|Pi3]]
WARNING: Unrecognized token: [[#The_remaining_intrusion_on_the_fifth_row|Pj3]]
WARNING: Unrecognized token: [[Template_VI1/Intrusion_on_the_4th_row|Pi4]]
WARNING: Unrecognized token: [[Template_VI1/Intrusion_on_the_3rd_row|Ph5]]
WARNING: Unrecognized token: [[Template_VI1/Intrusion_on_the_3rd_row|Pi5]]
WARNING: Unrecognized token: [[#The_remaining_intrusion_on_the_second_row_.28stub.29|Pg6]]
WARNING: Unrecognized token: [[#The_remaining_intrusion_on_the_second_row_.28stub.29|Pi6]]
WARNING: Unrecognized token: [[#One_remaining_intrusion_on_the_first_row_.28stub.29|Pf7]]
WARNING: Unrecognized token: [[#The_other_remaining_intrusion_on_the_first_row_.28stub.29|Pg7]]
WARNING: Unrecognized token: [[#The_other_remaining_intrusion_on_the_first_row_.28stub.29|Ph7]]
WARNING: Unrecognized token: [[#One_remaining_intrusion_on_the_first_row_.28stub.29|Pi7]]

Specific defense

For the moves that intersect all the carriers, Red has to find specific answers. Let's deal with the remaining intrusions!

One remaining intrusion on the first row (stub)

Details to follow

The other remaining intrusion on the first row (stub)

Details to follow

The remaining intrusion on the second row (stub)

The remaining intrusion on the third row (stub)

Red should go here:

1

See more details here.

The remaining intrusion on the fourth row

Red should move here (or the equivalent mirror-image move at "+"):

For more details, see this page.

The remaining intrusion on the fifth row

First establish a double ladder on the right.

17382546

Then use Tom's move:

53142